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Old 11-16-02, 12:28 PM
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Quick question

I would like to close up a wall before the elec comes by...so here is a quick question:

I just want to make sure that the following wiring sequence will work:

14/2 power supply to single-pole switch. 14/2 cable in one direction to light fixture 1. Second 14/2 in another direction to receptacle, where it continues on to another light fixture 2.

Will this work? The receptacle will always work even if the light switch is in the off position?

Thanks!
 
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Old 11-16-02, 01:04 PM
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It will work if you don't need the switch to switch the 2nd light.
 
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Old 11-16-02, 02:13 PM
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I want (need) for the switch to control both lights (otherwise, how do I turn on/off the second light?).

Can you propose a solution?

What if I go to Light 2 first, and then continue on with the 14/2 to the receptacle from Light 2.

Actually if it is more correct, can I do this:

Power to Switch. Cable 1 (14/2) from Switch to Light 1. Cable 2 (14/2) from Switch to Light 2. That is it; no connection to receptacle.

In order to get power to the receptacle, I instead feed off a totally separate switch that controls Light X, which is unrelated to either Lights 1 and 2. From Switch X, 14/2 goes to Light X and another 14/2 goes to the receptacle in question.

Bottom line, is how do I get power to that receptacle.

I really want to do the rough wiring so I can close up the walls tonight. Thanks.
 
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Old 11-16-02, 02:43 PM
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Your original wiring will do what you want if you don't mind the fact that the receptacle is switched too. Or you can simply run 14/3 (instead of 14/2) between the switch and receptacle and make the receptacle always on (or even half-switched if you want).

There are probably 50 ways to get this to work. We can't list them all. Some of the ways you've said will work, and some won't.

Here's a subset of the 50 options (S=switch; R=receptacle; L1=light1; L2=light2.

(A) Power to S. 14/2 from S to L1. 14/2 from L1 to L2. 14/2 from S to R.

(B) Power to S. 14/3 from S to R. 14/2 from R to L1. 14/2 from L1 to L2.

(C) Power to S. 14/2 from S to L1. 14/2 from S to R. 14/2 from S to L2. (You need a big box at S.)

(D) Power to L1. 14/2 from L1 to L2. 14/2 from L1 to R. 14/2 from L1 to S.

(E) Power to R. 14/2 from R to S. 14/2 from S to L1. 14/2 from L1 to L2.

(F) Power to R. 14/2 from R to S. 14/2 from S to L1. 14/2 from S to L2.

(G) Power to R. 14/2 from R to L1. 14/2 from L1 to L2. 14/2 from L1 to S.

I could go on forever, but my fingers are tired. Pick something.
 
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Old 11-16-02, 03:01 PM
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Thanks. The simplest solution seems to be your first recommendation: to replace the 14/2 between S and R with 14/3. I assume the 14/2 between R and L2 2 can remain.
 
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Old 11-16-02, 03:06 PM
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Yes. Between S and R, use the 14/3 red wire to carry switched power, and the 14/3 black wire to carry unswitched power. At the receptacle, connect the black of the 14/3 to the receptacle, and connect the red of the 14/3 to the black of the 14/2 (carrying switched power on to the light).
 
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Old 11-16-02, 05:56 PM
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Or you can run the 14-2 from the second light to the switch box instead of the recpt box.
Hope this helps
Brian
 
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