Is it possible to have a circuit not attached to a breaker?
#1
08-08-16, 12:47 PM
Join Date: Aug 2016
Location: USA
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Is it possible to have a circuit not attached to a breaker?
Hi-
I'm replacing a light in my kitchen, and can't figure out what circuit it is on.
I turned off each breaker, one at a time, and tested the light with voltage tester - there is no light in the fixture as it is broken and won't hold a bulb- and there was no breaker that killed the power to it. I did this a second time, same result. Then as a third test I turned off the main breaker to the house. That did the trick - no power to this light fixture.
So what do I conclude w/r/t what circuit this light fixture is on?
Many thanks in advance!
Cliff
I'm replacing a light in my kitchen, and can't figure out what circuit it is on.
I turned off each breaker, one at a time, and tested the light with voltage tester - there is no light in the fixture as it is broken and won't hold a bulb- and there was no breaker that killed the power to it. I did this a second time, same result. Then as a third test I turned off the main breaker to the house. That did the trick - no power to this light fixture.
So what do I conclude w/r/t what circuit this light fixture is on?
Many thanks in advance!
Cliff
#2
08-08-16, 12:54 PM
Member
If your trying to use a noncontact tester your getting a false reading.
Use a real volt Ohm meter.
Use a real volt Ohm meter.
#3
08-08-16, 01:04 PM
Group Moderator
Welcome to the forums.
No. But it is possible thru a wiring fault to have two circuits supplying power to the same device.
After the new fixture is installed and working..... go back thru all the breakers again to find it.
is it possible to have a circuit not attached to a breaker?
After the new fixture is installed and working..... go back thru all the breakers again to find it.
#4
08-08-16, 01:50 PM
Join Date: Aug 2016
Location: USA
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-I was using a non-contact tester. In fact I was checking with 2 different non-contact testers to be sure! So I will try again with a multi-tester. Thanks for the responses, will post results.
