Cutting tiles
#1
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Cutting tiles
I am installing a floor. There are 2 different tile types.
The first is 12x12 biege marble. This will be installed in diamond pattern.
The second is 12x12 orange marble. My wife wants me to cut the orange tiles into 2x2s and then insert a 2x2 square at the intersection of every diagonal
I am using a Ryobi 7 In. Portable Tile Saw with Laser
Model # WS750L
The width of the blade is .07 in which is a little bigger than 1/16th. Assuming i use 1/16 as the blade width, each 2x2 will really be 1 in and 15/16ths square.
If this is the case, when i lop off each corner to make the octogon (from the beige 12x12), how long should each cut be on the hypotenous of the small isosoles triange that I am removing
Now i want to measure to make the right cut. This is a isosoles right triange so I use c = sqrt(2a^2) since a=b
using a=31/32 (1in and 15/16)
I find C = 1.3700 or ~1 in and 3/8
Basically, I will measure 1 and 3/8 (on the tile edge) with the saw width on the discarded part and that should give me the perfect squares for my hypotenuous cuts.
Can someone check my math before I ruin some good tiles?
Thanks,
/Z
The first is 12x12 biege marble. This will be installed in diamond pattern.
The second is 12x12 orange marble. My wife wants me to cut the orange tiles into 2x2s and then insert a 2x2 square at the intersection of every diagonal
I am using a Ryobi 7 In. Portable Tile Saw with Laser
Model # WS750L
The width of the blade is .07 in which is a little bigger than 1/16th. Assuming i use 1/16 as the blade width, each 2x2 will really be 1 in and 15/16ths square.
If this is the case, when i lop off each corner to make the octogon (from the beige 12x12), how long should each cut be on the hypotenous of the small isosoles triange that I am removing
Now i want to measure to make the right cut. This is a isosoles right triange so I use c = sqrt(2a^2) since a=b
using a=31/32 (1in and 15/16)
I find C = 1.3700 or ~1 in and 3/8
Basically, I will measure 1 and 3/8 (on the tile edge) with the saw width on the discarded part and that should give me the perfect squares for my hypotenuous cuts.
Can someone check my math before I ruin some good tiles?
Thanks,
/Z
#2
1 15/16 converted to decimal is 1.9375x1.9375=3.753+3.753=7.506 Square root of 7.506 is 2.739.
Your hypotenuse on the approx 2" tiles will be almost 2 3/4"
Pythagorean theorem is Square root of the sum of the two sides squared.
Your hypotenuse on the approx 2" tiles will be almost 2 3/4"
Pythagorean theorem is Square root of the sum of the two sides squared.
#3
Just wondering....won't you have 4 sharp square edges of every 2x2 you cut? That's a lot of beveling and polishing it seems like.
#4
Member
Z
Is this marble going down on a cement slab or a framed wood floor? If its a framed wood floor, have you checked to make sure the structure is strong/stiff enough to support a natural stone installation. Natural stone floors have to be twice as strong/stiff as that for ceramic tile floors.
Is this marble going down on a cement slab or a framed wood floor? If its a framed wood floor, have you checked to make sure the structure is strong/stiff enough to support a natural stone installation. Natural stone floors have to be twice as strong/stiff as that for ceramic tile floors.